We say that an integral domain R satisfies property (*) if the ideal boolean AND(n>0) a(n)R is prime, for every non-unit a E R. We investigate property (*) in the classical situation when R is the integral closure of a valuation domain V in a finite extension L of the field of fractions Q of V. Let f be the irreducible polynomial of an integral element x such that L = Q[x]. Assuming that the discriminant of f is a unit, we prove that R is not a valuation domain if f has roots modulo P, the maximal ideal of V. Then we show that R does not satisfy (*) if f has roots in V modulo J, for a suitable non-maximal prime ideal J not equal 0 of V. Moreover, if f has degree 2 or 3 the converses of the above results are true. Examples show that these converses are no longer valid for any degree n greater than or equal to 4. (C) 2003 Elsevier B.V. All rights reserved.
Intersections of powers of a principal ideal and primality
ZANARDO, PAOLO
2004
Abstract
We say that an integral domain R satisfies property (*) if the ideal boolean AND(n>0) a(n)R is prime, for every non-unit a E R. We investigate property (*) in the classical situation when R is the integral closure of a valuation domain V in a finite extension L of the field of fractions Q of V. Let f be the irreducible polynomial of an integral element x such that L = Q[x]. Assuming that the discriminant of f is a unit, we prove that R is not a valuation domain if f has roots modulo P, the maximal ideal of V. Then we show that R does not satisfy (*) if f has roots in V modulo J, for a suitable non-maximal prime ideal J not equal 0 of V. Moreover, if f has degree 2 or 3 the converses of the above results are true. Examples show that these converses are no longer valid for any degree n greater than or equal to 4. (C) 2003 Elsevier B.V. All rights reserved.
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